Question

Solve for $x$:\\ $2^x = 29$\\ $x = $\\ You may enter the exact value or round to 4 decimal places.

          Solve for $x$:\\
$2^x = 29$\\
$x = $\\
You may enter the exact value or round to 4 decimal places.
        
Solve for x:

2^x = 29

x =

You may enter the exact value or round to 4 decimal places.

Added by Teresa B.

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Precalculus with Limits
Precalculus with Limits
Ron Larson 2nd Edition
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Solve for x: 2^(x) = 29 x = You may enter the exact value or round to 4 decimal places. Solve for: 2 = 29 You may enter the exact value or round to 4 decimal places.
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Transcript

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00:02 Hi, now given e to the power x is equal to 3 .116, we have to find the value of x.
00:10 So now taking ln on both sides, ln to the power x is equal to ln 3 .116.
00:20 So now this is x, ln 3 .116 is 1 .1365.
00:30 Now this implies that x lne is 1 is equal to 1 .1365.
00:39 So now from here we can find the value of x...
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