00:01
Problem, we're being asked to solve the given system of equations.
00:03
Remember, that means we're trying to find the value of x -y.
00:06
So, in order to do this, i'm going to use the elimination method.
00:10
So what i'm going to do is i'm going to subtract the two equations together and hope that one of our variables cancels out.
00:16
We'll notice for our xes, we have 0 .2x minus 0 .2x, which is equal to 0 .2x, which is equal to 0 .2, and lastly, we have 0 .2 minus 0 .4, which is equal to negative 0 .2.
00:37
So now, to solve for y, we just need to divide both sides of our equation by negative 0 .3.
00:43
So the easiest way to do this, we can move the decimal place, one place to the right in each, and two negatives make a positive, which means y will equal to two thirds.
00:51
Well, now that we've solved for y, we need to find x.
00:54
So what i'm going to do is i'm going to take my first equation, which was 0 .2x, and and i believe it was minus 0 .1y equal to 0 .2.
01:05
And now we can substitute 2 thirds in place of y...