Solve the initial value problem: 1. x' = xcos(t), x(0) = 1 2. x' = (t+1)(cos(x))^2, x(0) = 1
Added by Barbara R.
Step 1
To solve the first initial value problem, we can use separation of variables. We have: dx/dt = xcos(t) Dividing both sides by xcos(t), we get: 1/x dx = cos(t) dt Integrating both sides, we get: ln|x| = sin(t) + C where C is the constant of integration. To Show more…
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