Question

The speed of the Airbus A340 plane is 190 km/h. The coefficient of friction between its wheels and the tarmac is 0.08. The braking system of the plane and the air drag combined are able to decrease the speed at a rate of 0.6 m/s². What is the safe length of the runway?

          The speed of the Airbus A340 plane is 190 km/h. The coefficient of friction between its wheels and the tarmac is 0.08. The braking system of the plane and the air drag combined are able to decrease the speed at a rate of 0.6 m/s². What is the safe length of the runway?
        
Show more…

Added by Isabella H.

University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
The speed of the Airbus A340 plane is 190 km/h. The coefficient of friction between its wheels and the tarmac is 0.08. The braking system of the plane and the air drag combined are able to decrease the speed at a rate of 0.6 m/s². What is the safe length of the runway?
Close icon
Play audio
Feedback
Powered by NumerAI
Danielle Fairburn Jennifer Stoner
Kathleen Carty verified

Meghan Miholics and 96 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question

*

Labs

-

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

*

Key Concepts

-
Key Concept
Premium Feature
Explore the core concept behind this problem.
Play button
Key Concept
Premium Feature
Explore the core concept behind this problem.
Your browser does not support the video tag.

*

Recommended Videos

-
an-airbus-a320-jetliner-has-a-takeoff-mass-of-75000-kg-it-reaches-its-takeoff-speed-of-82-mathrmm-ma

An Airbus A320 jetliner has a takeoff mass of 75,000 kg. It reaches its takeoff speed of $82 \mathrm{m} / \mathrm{s}(180 \mathrm{mph})$ in $35 \mathrm{s}$. What is the thrust of the engines? You can neglect air resistance but not rolling friction.

Physics for Scientist and Engineers: A Strategic Approach

an-airbus-a-320-jetliner-has-a-takeoff-mass-of-75000-mathrmkg-it-reaches-its-takeoff-speed-of-82-mat

An Airbus A 320 jetliner has a takeoff mass of $75,000 \mathrm{~kg}$. It reaches its takeoff speed of $82 \mathrm{~m} / \mathrm{s}(180 \mathrm{mph})$ in $35 \mathrm{~s}$. What is the thrust of the engines? You can neglect air resistance but not rolling friction.

College Physics: A Strategic Approach Volume 1

an-airbus-a320-jetliner-has-a-takeoff-mass-of-75000kg-it-reaches-its-takeoff-speed-of-8494ms-190mph-in-36s-the-coefficient-friction-of-rubber-rolling-on-concrete-002-what-is-the-thrust-of-th-40646

An Airbus A320 jetliner has a takeoff mass of 75,000 kg. It reaches its takeoff speed of 84.94 m/s (190 mph) in 36 s. The coefficient of friction of rubber rolling on concrete is 0.02. What is the thrust of the engines? You can neglect air resistance but not rolling friction.

Mahendra K.


*

Recommended Textbooks

-
University Physics with Modern Physics

University Physics with Modern Physics

Hugh D. Young 14th Edition
achievement 1,676 solutions
Physics: Principles with Applications

Physics: Principles with Applications

Douglas C. Giancoli 7th Edition
achievement 1,644 solutions
Fundamentals of Physics

Fundamentals of Physics

David Halliday, Robert Resnick , Jearl Walker 10th Edition
achievement 1,268 solutions

*

Transcript

-
00:01 In this question, we have an airplane with a given mass, and it reaches a takeoff speed in 82 meters per second in 35 seconds.
00:12 And we're asked to calculate the thrust of the engines.
00:15 We can neglect air resistance, but not rolling friction.
00:20 So in order to do this question, we definitely need to use f9 equals ma, but we don't know acceleration.
00:29 So i think the first thing to try to calculate is the acceleration.
00:36 And of course we're given a final speed of 82 meters per second.
00:40 Presumably the airplane is starting from rest.
00:44 And we also know a time is 35 seconds.
00:48 So we can calculate acceleration here as just delta v over delta t.
00:54 The delta v is 82, this 82 minus zero.
01:00 And then the time is 35.
01:03 So if you place that into a calculator, you will get an acceleration of 2 .34 meters per second squared.
01:12 So now that we have the acceleration, we can do an f -net equation.
01:20 And in terms of a free body diagram, we know that the engines are going to be providing a thrust force forward.
01:28 So i'm going to label that as f -t.
01:30 And then there's going to be a rolling friction force pulling the plane back, kind of opposing the motion, i should say.
01:40 So the net force is going to be composed of ft minus ff...
Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever