State the equation of $f(x)$ if its domain is $\{x \in R | x \neq -\frac{1}{4}\}$ and the y-intercept is $(0, 3)$. $f(x) = \frac{x-3}{4x-1}$ $f(x) = \frac{x+3}{4x-1}$ $f(x) = \frac{3}{4x+1}$ $f(x) = \frac{x-3}{4x+1}$
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The domain is given as $\{x \in R | x \neq -\frac{1}{4}\}$. For a rational function, the domain is restricted when the denominator is zero. Therefore, the denominator of $f(x)$ must be zero when $x = -\frac{1}{4}$. This means that $4x+1$ must be a factor of the Show more…
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