Suppose a polynomial of degree 4 with rational coefficients has the given numbers as zeros. Find the other zero. -1, √3, 9
Added by Alberto C.
Step 1
In this case, the irrational root is $\sqrt{3}$, so its conjugate is $-\sqrt{3}$. Now we have four roots: $-1, \sqrt{3}, -\sqrt{3}, 9$. So the polynomial can be written as: Show more…
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