Question

Suppose that \sin A = 0.71. What is the angle A (in degrees) in the second quadrant (your answer should between $90^\circ$ and $180^\circ$)? Please round your answer to one decimal place.

          Suppose that \sin A = 0.71. What is the angle A (in degrees) in the second quadrant (your answer should between $90^\circ$ and $180^\circ$)? Please round your answer to one decimal place.
        
Suppose that sinA = 0.71. What is the angle A (in degrees) in the second quadrant (your answer should between 90^∘ and 180^∘)? Please round your answer to one decimal place.

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Precalculus with Limits
Precalculus with Limits
Ron Larson 2nd Edition
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Suppose that sin A = 0.71. What is the angle A (in degrees) in the second quadrant (your answer should be between 90° and 180°)? Please round your answer to one decimal place.
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Transcript

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00:01 So we're given the cosine of a, and that's negative 0 .79.
00:06 And we're told the sine of a is greater than 0.
00:10 Cosine is negative and sine is positive, that means a is in quadrant 2, which is between pi over 2 and pi.
00:23 We want to first determine the quadrant for a over 2.
00:29 So if a is between pi and pi over 2, then we're just going to divide everything by a half, and that tells me that the half angle is between pi over 2 and pi over 4.
00:48 So that half angle is in quadrant 1.
00:58 Now i want the sine of a.
01:02 So if my cosine is negative 0 .79, that's another way of saying negative 79 over 100...
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