Question

Suppose that the function $f$ is defined, for all real numbers, as follows. $f(x) = \begin{cases} -2 & \text{if } x \le -1 \\ (x-1)^2 - 2 & \text{if } -1 < x < 2 \\ \frac{1}{2}x + 1 & \text{if } x \ge 2 \end{cases}$ Find $f(-4)$, $f(-1)$, and $f(1)$. $f(-4) = $ $f(-1) = $ $f(1) = $

          Suppose that the function $f$ is defined, for all real numbers, as follows.
$f(x) = 
\begin{cases}
-2 & \text{if } x \le -1 \\
(x-1)^2 - 2 & \text{if } -1 < x < 2 \\
\frac{1}{2}x + 1 & \text{if } x \ge 2
\end{cases}$
Find $f(-4)$, $f(-1)$, and $f(1)$.
$f(-4) = 
$
$f(-1) = 
$
$f(1) = 
$

Suppose that the function f is defined, for all real numbers, as follows.
f(x) =

-2 if x ≤ -1

(x-1)^2 - 2 if -1 < x < 2
(1)/(2)x + 1 if x ≥ 2
Find f(-4), f(-1), and f(1).
f(-4) =
f(-1) =
f(1) =

Added by Katelyn S.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Harsha M

02/10/2022

Step 1

Step 1: Since -4 ≤ -1, we use the first part of the piecewise function to find f(-4). Show more…

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Suppose that the function $f$ is defined, for all real numbers, as follows. $$f(x) = \begin{cases} -2 & \text{if } x \le -1 \\ (x-1)^2 - 2 & \text{if } -1 < x < 2 \\ \frac{1}{2}x + 1 & \text{if } x \ge 2 \end{cases}$$ Find $f(-4), f(-1),$ and $f(1)$. f(-4) = f(-1) = f(1) =