suppose that variable X is normally distributed with mean of 55 and standard deviation of 23. What is the probobility that X is between 46 and 71 (round results to two decimals).
Added by Patricia J.
Step 1
For X = 46: \[ Z_1 = \frac{46 - 55}{23} = \frac{-9}{23} \approx -0.39 \] For X = 71: \[ Z_2 = \frac{71 - 55}{23} = \frac{16}{23} \approx 0.69 \] Show more…
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