Suppose you are playing a gambling game where you spin the...

Suppose you are playing a gambling game where you spin the following spinner +$40 -$25 -$75 $0 +$100 followed by rolling a fair four-sided die, which multiplies the monetary value from the spinner. (a) Let X be the random variable that gives the resulting monetary value (that you either win or lose). What are the possible values X can take on? (b) Now let X be just the monetary value the spinner lands on. Suppose the probability distribution is as follows. P(X = $100) = \frac{1}{18} P(X = -$25) = \frac{2}{9}

Transcript

00:01 Hi, i'm david and i'm hedjay, happy i'm seeing your question.

00:03 Now let me bring up your question here.

00:06 In the question here, we're going to perform the experiment that rolling in a die, and we have the x will be defined as the amount you are rewarded after one run, and that will be equal to the number of the dot on the top side.

00:27 And therefore, in the question one, the question asked, to find one is the possible value on the random robot x.

00:37 So the possible value of the x will be because the die it can take the value on the 1, 2, 3, 4, 5 and 6, and that will be the answer for the number 1.

00:54 For the number 2, we need to write down the property mass function on the x.

01:00 So here we will have the x and the probability of the x.

01:05 And x can tend the value the 1, 2, 3, 4, 5 and 6.

01:14 And because the outcome here it will be equally likely for any number it can be, so it can be the 1 over 6 for each.

01:27 And that's will be the answer for the part p, the probability must function on the random robot x.

01:34 Now for the question 3, 1 2 write out explicit cumulative distribution so let me extend this column here.

01:48 And from here i want to find the probability.

01:52 So the cumulative will have the form of probability to the x -moly equal to the x.

01:57 So the first value will be the 1 over 6.

02:00 The next one will add up from the 1 and 2nd.

02:03 Then we have the 2 over 6.

02:05 From the next one will end up on 3 of them.

02:08 We have 3 over 6...

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