Question

Metal Diameter Metal Area (cm²) Time (s) (cm) Temp. Increase (°C) 0 0 Aluminum (small) 0.42 .14 16 1 29 2 45 3 0 0 Aluminum (medium) 0.5 .20 20 1 30 2 37 3 0 0 Aluminum (large) 0.64 .32 13 1 24 2 36 3 0 0 Brass (medium) 0.5 .20 24 1 41 2 63 3 0 0 Steel (medium) 0.5 .20 98 1 140 2 187 3 Table 3: Data ANALYSIS & QUESTIONS 1. On graph 1 plot the temperature as a function of time for the three aluminum rods. Draw a best-fit line for each of the rods. Be sure to label axes, and label each best fit line as small, medium, or large diameter rod. 2. On graph 2 plot the temperature as a function of time for the same size brass, stainless steel and aluminum rods. Draw a best-fit line for each of the rods. Be sure to label axes, and label the metal of each best fit line. $\frac{Q}{t} = \frac{KA\Delta T}{l}$ 3 3. For increasing values of the diameter of the aluminum rod, how does the heat conduction rate change? Does this agree with equation 1? Explain using evidence from your plot.

          Metal Diameter
Metal
Area (cm²)
Time (s)
(cm)
Temp. Increase
(°C)
0
0
Aluminum (small)
0.42
.14
16
1
29
2
45
3
0
0
Aluminum (medium)
0.5
.20
20
1
30
2
37
3
0
0
Aluminum (large)
0.64
.32
13
1
24
2
36
3
0
0
Brass (medium)
0.5
.20
24
1
41
2
63
3
0
0
Steel (medium)
0.5
.20
98
1
140
2
187
3
Table 3: Data
ANALYSIS & QUESTIONS
1. On graph 1 plot the temperature as a function of time for the three aluminum rods. Draw
a best-fit line for each of the rods. Be sure to label axes, and label each best fit line as small,
medium, or large diameter rod.
2. On graph 2 plot the temperature as a function of time for the same size brass, stainless steel
and aluminum rods. Draw a best-fit line for each of the rods. Be sure to label axes, and label the
metal of each best fit line.
$\frac{Q}{t} = \frac{KA\Delta T}{l}$
3
3. For increasing values of the diameter of the aluminum rod, how does the heat conduction rate
change? Does this agree with equation 1? Explain using evidence from your plot.

Show more…

Metal Diameter
Metal
Area (cm²)
Time (s)
(cm)
Temp. Increase
(°C)
0
0
Aluminum (small)
0.42
.14
16
1
29
2
45
3
0
0
Aluminum (medium)
0.5
.20
20
1
30
2
37
3
0
0
Aluminum (large)
0.64
.32
13
1
24
2
36
3
0
0
Brass (medium)
0.5
.20
24
1
41
2
63
3
0
0
Steel (medium)
0.5
.20
98
1
140
2
187
3
Table 3: Data
ANALYSIS QUESTIONS
1. On graph 1 plot the temperature as a function of time for the three aluminum rods. Draw
a best-fit line for each of the rods. Be sure to label axes, and label each best fit line as small,
medium, or large diameter rod.
2. On graph 2 plot the temperature as a function of time for the same size brass, stainless steel
and aluminum rods. Draw a best-fit line for each of the rods. Be sure to label axes, and label the
metal of each best fit line.
(Q)/(t) = (KAΔ T)/(l)
3
3. For increasing values of the diameter of the aluminum rod, how does the heat conduction rate
change? Does this agree with equation 1? Explain using evidence from your plot.

Added by -Scar M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Madhur L

05/25/2023

Step 1

Label the x-axis as time (s) and the y-axis as temperature (C). Draw a best-fit line for each of the rods (small, medium, and large diameter) based on the data provided. Show more…

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Thanks for your feedback!

able[[Metal, able[[Metal Diameter],[(cm) Need #3 Metal Diameter cm) Area (cm Time (s) Temp.Increase C 0 Metal 0 16 29 45 0 20 30 37 Aluminum (small) 0.42 hi' 2 3 0 Aluminum (medium) 0.5 20 2 3 Aluminum (large) h9 g .32 2 3 0 Brass (medium) 0.5 20 2u 4i 63 0 98 140 187 1 2 3 0 Steel (medium) 0.5 20 1 2 Table 3:Data ANALYSIS &QUESTIONS 1. On graph 1 plot the temperature as a function of time for the three aluminum rods.Draw a best-fit line for each of the rods. Be sure to label axes and label each best fit line as small medium, or large diameter rod. 2. On graph 2 plot the temperature as a function of time for the same size brass,stainless steel and aluminum rods. Draw a best-fit line for each of the rods. Be sure to label axes, and label the metal of each best fit line. Q WALT 3. For increasing valucs of the diameter of the aluminum rod, how docs the heat conduction rate change? Dos this agree with equation 1? Explain using evidence from your plot.

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Transcript

00:01 Hello students, in this question we have the time length change graph we need to plot so let's do that so this is the two axes that we are going to use so this is the length axis and this is the time axis so for the first 4 .54 kilogram is 4 .54 kilogram let's do that it start with a time frequency of 0 .25 and then 0 .5 then 1 and then 2 then again 4 6 8 12 16 and then go 20 so it what happens is that it starts with 0 at 0 it starts with 0 at let's draw a change as well so this is 25 .25 this is 0 .50 this is 0 .75 and this is 1 and we have changes as well so 2 3 so it's not a linearly increasing graph 4 5 6 7 etc so what is happening here so the for the first graph it is starting from 0 it goes to 0 .28 okay so it goes here and then it goes from 0 .36 goes here then it goes to 0 .48 goes here okay and then it goes to 0 .71 0 .71 in 2 right so in 2 so it goes like this okay in 2 okay so this graph is linear it's going up the trend is linear okay and for the second graph which is the 6 .80 if you draw it starts from 0 0 .46 0 .66 and 0 .91 okay it starts from 0 .46 it starts goes to and then 0 .66 it goes in the next stage then 0 .91 in the third stage this is also going like this so i am just abstractly representing this but you can draw this thing it's almost linearly growing okay and for the third one also it will be growing linearly they're not going to look at every aspect of it but it starts from 0 it goes to 0 .69 6 9 so it's a higher curve so this is the curves that you obtain right now is this behavior dominated by transient or steady -state creep or both occurs so let's look at those so strain is given by the equation the strain is equal to e is equal to length change delta l by original length and then steady -state creep e dot is given as strain by time right so it's strain by time that is the or e by time that is the creep rate the relationship between steady -state creep and stress is e dot will be equal to a times sigma raised to n so that is the relation between that so…

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