00:01
Okay, so we're gonna do first the interpretation of levene's test.
00:12
So levene's test is used to assess the equality of variances across groups, and the new hypothesis of levene's test states that the group variances are equal, which means that there is homogeneity of variances.
00:39
Now, if the test results in a p -value less than the chosen significance level, we reject the new hypothesis and conclude that the variances are not equal, which indicates that the assumption of homogeneity of variances is violated.
01:14
Okay, so based on the levin's test results provided, we have f of 2 .898 degrees of freedom between groups of 2, degrees of freedom within groups of 1 or 2, and p -value of 0 .06, we have that the p -value is greater than 0 .05, which is a common significance level, then this implies that we fail to reject the new hypothesis of levine's test.
01:59
So we can conclude that the assumption of the homogeneity of variances is not violated.
02:04
So, this implies that the variances across the groups are statistically similar enough to proceed with analysis that assume equal variances, such as anova.
02:38
And also, means and standard deviations of quiz 3 for each group...