3) Test Statistic: Situation 1: \(\sigma\) known TS: \(z = \frac{x-\mu}{\sigma/\sqrt{n}}\) \(z = \frac{2800-2200}{790/\sqrt{30}} \implies 4.16\) 4) p-value: P-value = P(Z>TS) right-tailed Ex: (In the slides): Ems Ambulance Service example H0: \(\mu \le 12\) mins HA: \(\mu > 12\) mins TS: z = 2.47 p-value: z-dist'n right-tailed test p-value = P(Z>TS) = P(Z>2.47) = 1-P(Z\le 2.47) = 1 - 0.9932 = 0.0068 = P(z > 4.16) = 1 - P(z \le 4.16) = 1 -
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48) TS = 600 / 144.92 TS ≈ 4.14 Show more…
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Sri K.
b-2. Find the p-value. 0.01 ≤ p-value < 0.025 p-value < 0.01 p-value ≥ 0.10 0.05 ≤ p-value < 0.10 0.025 ≤ p-value < 0.05 c-1. At the 5% significance level, what is your conclusion? H0 and conclude at the 5% significance level that at least one of the proportions have changed from the historical rates.
Calculate the test statistic and p-Value for each sample mean. Round to 3 decimals. H0: μ ≤ 15 versus H1: μ > 15, α = 0.05, x̄ = 17, s = 8, n = 29 35. Test statistic 36. p-Value 37. Decision (choose one) Reject the H0 Fail to reject the H0 H0: μ ≥ 205 versus H1: μ < 205, α = 0.05, x̄ = 198, σ = 20, n = 25 38. test statistic 39. p-Value 40. Decision (choose one) Reject the H0 Fail to reject the H0
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