Add 6 to both sides of the equation:
$$y^2 - 6y + 6 = 0$$
Now, we can identify the coefficients a, b, and c:
$$a = 1$$
$$b = -6$$
$$c = 6$$
Step 2:
The quadratic formula is given by:
$$y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$
Substitute the values of a, b, and c
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