Question

A wire having a uniform linear charge density \lambda is bent into the shape shown in the figure below. Find the electric potential at point O. (Use the following as necessary: $k$, $k_e$ and \lambda)\\ $V = k_e \lambda \cdot (\pi - 2\ln(3))$

          A wire having a uniform linear charge density \lambda is bent into the shape shown in the figure below. Find the electric potential at point O. (Use the following as necessary: $k$, $k_e$ and \lambda)\\
$V = k_e \lambda \cdot (\pi - 2\ln(3))$

A wire having a uniform linear charge density λis bent into the shape shown in the figure below. Find the electric potential at point O. (Use the following as necessary: k, ke and λ)

V = ke λ· (π - 2ln(3))

Added by Roy L.

University Physics with Modern Physics

Hugh D. Young 14th Edition

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Solved by Expert Khoobchandra Agrawal

04/06/2022

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We are given that the wire has a uniform linear charge density λ and it is bent into a specific shape. We need to find the electric potential at point O. Show more…

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Texts: A wire having a uniform linear charge density λ is bent into the shape shown in the figure below. Find the electric potential at point O. Use the following as necessary: K and √(x-a-(-21n(3))) / 2R.