00:01
Okay, so we want to calculate the rate of which heat energy is given per unit area on a black body, all right, at a temperature of 273 kelvin.
00:10
Now, the equation that we're going to employ over here is giving us h is equal to e times stefan bousman constant times the temperature to the power of 4.
00:20
All right.
00:22
Now, since the question is asking us to calculate the heat energy per unit area, we're going to restructure this equation to suit what we've been asked.
00:32
So we have h0 by a is equal to e to the power sigma times t to the power 4.
00:41
We know the temperature that we've been given is 273 kelvin.
00:48
And then the stefan bozeman constant is usually given us 5 .6, 7 times 10 to the power negative 8 watts per meter squared per kelvin to the power 4.
01:02
All right.
01:05
Now emissivity usually is equal to 1.
01:07
All right so when we factor all of this into our equation then we have we have um then cbt 1 multiplied by stephan bosman constant 5 .6 7 times 10 to the power negative 8 multiplied by interracket 273 to the power 4 which is the temperature kelvin all right now when you multiply all of this this should give you you 314 .9 watts per meter squared.
01:59
All right so this is what it should give us.
02:02
Now we've also been told that if the temperature is at 2730 kelvin then what would that also be? if the temperature is at 2730 kelvin what would that also be? if the temperature is at 2730 kelvin what would that also be? all right.
02:18
So let's take a look at that as well...