00:01
All right, here's our setup with capacitor 1, 2, and 3 all in parallel with each other.
00:07
We're told that the voltage supply to the system is 470 volts.
00:11
C1 is 1 .5 microferds, c2 is 4 .9 microferds, c3 is 5 .7 microferds.
00:18
Now, part a asks about the voltage cross c1, and since these are all in parallel, we know that the voltage across each one of these paths has to be the same as the voltage that is being supplied, because the potential here and the potential here is what determines the potential difference.
00:39
And so the potential difference across c1 is the same as the potential difference across c2, which is the same as the potential difference across c3, and that has to be equal to the potential that we get from the battery, so 470 volts.
00:55
Now, this is also the answer to c and e, because the potential difference across each of these resistors is the same.
01:06
So now let's look at part b.
01:08
The charge across c1 is given by the capacitance of c1 times that voltage drop.
01:17
So c1 times 470...