00:01
For the first item, we have to use the equation for the magnitude of the gravitational force, which is the following.
00:07
The magnitude is given by newton's constant times the mass of the first object, times the mass of the other object, divided by the distance in between them squared.
00:19
Then, using the data given by the problem, we have 6 .67 times 10 to minus 11 times the mass of the earth, which is 5 .98 times 10 to 24 times the mass of the satellite, which is 425 kilograms.
00:41
And this is divided by the distance between the satellite and the center of the earth.
00:47
And this distance is given by two times the radius of the earth.
00:51
Then we have two times 6 .38 times 10 to the 6 squared.
01:00
And these results in a gravitational force of approximately 1 ,040 neutrons, which you can write as 1 .04 times 10 to the 3rd neutons.
01:12
It means that the earth is exerting a force on the spaceship, attracting it, and at the same time the spaceship is attracting earth with a force of the same magnitude but opposite direction.
01:27
So, on the second item, we have to calculate what is the magnitude of the gravitational force exerted on the earth by the satellite.
01:36
It happens that the gravitational force exerted on the earth by the satellite has the same magnitude as the gravitational force exerted on the satellite by the earth.
01:45
There is a symmetry in the gravitational force.
01:47
So again, we have 1 .04 times 10 to the third neutrons.
01:52
On the next item, we have to calculate the satellite's acceleration.
01:56
For that we have to use newton's second law...