Question

Resolver por el método gráfico 8.- a) Max: Z = 4X1 +5X2 S.A X1 + 2X2 ? 10 5X1+3X2 ? 30 X1, X2 ? 0 b) Min: Z = 10X1 +15X2 S.A X1 + X2 ? 10 3X1 + X2 ? 12 -2X1+3X2 ? 3 X1, X2 ? 0

          Resolver por el método gráfico
8.- a) Max: Z = 4X1 +5X2
S.A
X1 + 2X2 ? 10
5X1+3X2 ? 30
X1, X2 ? 0
b) Min: Z = 10X1 +15X2
S.A
X1 + X2 ? 10
3X1 + X2 ? 12
-2X1+3X2 ? 3
X1, X2 ? 0

Added by Matthew S.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Sri K

02/26/2023

Step 1

The feasible region is the region that satisfies all the given constraints. The given constraints are: 1) X1 + 2X2 ≤ 10 2) X1 + X2 ≤ 10 3) 5X1 + 3X2 ≤ 30 4) 3X1 + X2 ≥ 12 5) X1, X2 ≥ 0 6) -2X1 + 3X2 ≤ 3 7) X1, X2 ≥ 0 To graph these constraints, we can start by Show more…

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Texts: Resolver por el método gráfico 8.-a) Max: Z = 4X1 + 5X2 b) Min: Z = 10X1 + 15X2 V'S S.A X1 + 2X2 ≤ 10 X1 + X2 ≤ 10 5X1 + 3X2 ≤ 30 3X1 + X2 ≥ 12 X1, X2 ≥ 0 -2X1 + 3X2 ≤ 3 X1, X2 ≥ 0