Texts you are given a vector in the xy plane that has a...

Name: texts you are given a vector in the xy plane that has a magnitude of 800 units and a y component of 630 units a what are two possibilities for its x direction b assuming the x component is k 26384
Uploaded: 2022-03-28T23:55:48-08:00
Duration: 7 min 42 s
Channel: Paul Gabriel
Description: texts you are given a vector in the xy plane that has a magnitude of 800 units and a y component of 630 units a what are two possibilities for its x direction b assuming the x component is k 26384

Texts: You are given a vector in the xy plane that has a magnitude of 80.0 units and a y component of -63.0 units. a.) What are two possibilities for its x direction? b.) Assuming the x component is known to be positive, specify the magnitude of the vector which, if you add it to the original one, would give a resultant vector that is 80.0 units long and points entirely in the -x direction. c.) Specify the direction of the vector.

Transcript

00:01 We're given a vector in the xy plane that has a magnitude of 19 units and the y component is minus 68 units there are two possibilities for its x components.

00:09 So what we have is the magnitude it's called us v for the vector is called the magnitude of the vector plus the y component squared and so we have that this vx is unknown vy is minus 68 squared that and the minuses 90 so we have vx squared is equal to square of 90 squared minus minus 68 squared and this is going to be plus or minus the square of that because if you square minus you also get down that value so this is equal to this is v x not vx squared 50 plus or minus 58 0 .95 separate xmits 2 plus or minus 59 units so it could be plus 59 units or minus 59 units and then uxmobinant is known to be positive specify the magnitude of the vector which if you added to the original one would give you a resultant of 80 units so what we have for this second one is we have a vector v which has a the magnitude of 80 to 90 units and then we have a second vector it's called at you the magnitude is unknown and we have the resultant magnitude of 80 and points entirely in the x direction so what that means is that the y component is going to cancel out so that means our new vector you would have 68 u x for our new vector over 68 units in the y direction because once it adds up to minus 68 for the first one we have resultant of zero in the y direction leaving only the x direction then for the x vx plus ux must be equal to the resultant rx the x of that and the resultant only has an x -combinant which is 80 ux is unknown and vx is plus 59 units and i'm all that is positive even the same to be positive so 59 plus ux is equal to 80 so ux we call to 21 units so basically we have something like this this would be okay so um the resultant are it's going to be in negative x direction so this should be minus 80 here instead until we get minus 139 units so we have this 80 and then you have the my components of the first one that's minus 68 then the my component of the second one that's the x component of the first one is 59 units to the right.

05:21 The x component of the second one is going to be one that's nine units left.

05:35 So that the sum of the two vectors will give us a resultant of 18.

05:42 Now for the third one, we're seeing to find the magnitude actually...

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