Question

3. The 100-lb block is stationary at time $t = 0$, and then it is subjected to the force $P$ shown. Note that the force is zero for all times beyond $t = 20$ sec. If $\mu_s = 0.6$, $\mu_k = 0.4$, and $\theta = 25^\circ$, determine the velocity $v$ of the block at time $t = 25$ sec. Also, calculate the time $t$ at which the block comes to rest again. ($v = 89.4$ ft/sec, the block never stops)

Name: 3. The 100-lb block is stationary at time t = 0, and then it is subjected to the force P shown. Note that the force is zero for all times beyond t = 20 sec. If = 0.6, = 0.4, and θ = 25^∘, determine the velocity v of the block at time t = 25 sec. Also, calculate the time t at which the block comes to rest again. (v = 89.4 ft/sec, the block never stops)
Uploaded: 2021-09-27T12:31:59-08:00
Duration: 3 min 32 s
Channel: Umar Sohail Qureshi
Description: 3. The 100-lb block is stationary at time t = 0, and then it is subjected to the force P shown. Note that the force is zero for all times beyond t = 20 sec. If = 0.6, = 0.4, and θ = 25^∘, determine the velocity v of the block at time t = 25 sec. Also, calculate the time t at which the block comes to rest again. (v = 89.4 ft/sec, the block never stops)

          3. The 100-lb block is stationary at time $t = 0$, and then it is subjected to the force $P$ shown. Note that the force is zero for all times beyond $t = 20$ sec. If $\mu_s = 0.6$, $\mu_k = 0.4$, and $\theta = 25^\circ$, determine the velocity $v$ of the block at time $t = 25$ sec. Also, calculate the time $t$ at which the block comes to rest again. ($v = 89.4$ ft/sec, the block never stops)

3. The 100-lb block is stationary at time t = 0, and then it is subjected to the force P shown. Note that the force is zero for all times beyond t = 20 sec. If = 0.6, = 0.4, and θ = 25^∘, determine the velocity v of the block at time t = 25 sec. Also, calculate the time t at which the block comes to rest again. (v = 89.4 ft/sec, the block never stops)

Added by Silvia B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Umar Sohail Qureshi

09/27/2021

Step 1

The normal force $ N $ can be calculated as $ N = W = 100 \text{ lb} $. The friction force can be calculated as $ F_f = \mu_k N = 0.4 \times 100 = 40 \text{ lb} $. Show more…

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The 100-1b block is stationary at time t=0, and then it is subjected to the force P shown. Note that the force is zero for all times beyond t=20sec. If mu _(s)=0.6,mu _(k)=0.4, and heta =25deg , determine the velocity v of the block at time t=25sec. Also, calculate the time t at which the block comes to rest again. ( v=89.4f(t)/(sec), the block never stops) 3. The 100-lb block is stationary at time t = 0. and then it is subjected to the force P shown. Note that the force is zero for all times beyond t = 20 sec. If s = 0.6, k = 0.4, and 0 = 25, determine the velocitv v of the block at time t = 25 sec. Also. calculate the time t at which the block comes to rest again.( = 89.4 ft/sec, the block never stops) P,lb 15 W Us,lk 10 0 t,sec 10 20