The acceleration due to gravity is inversely proportional to the square of the distance from the centre of Earth. The acceleration due to gravity for a satellite orbiting 7000km above the centre of Earth is 8.2(m)/(s^(2)).
a) Write a formula for this relationship.
b) Sketch a graph of the relation.
c) At what height will the acceleration due to gravity be 6.0(m)/(s^(2)) ?
When a saw is used to cut wood, a certain percent is lost as sawdust, depending on the thickness of the saw-blade. The wood lost is called the kerf. The percent lost, P(t), can be modelled by the function P(t)=(100t)/(t+W), where t is the thickness of the blade and W is the thickness of the wood, both in millimetres. Consider a saw cutting a 30 -mm-thick piece of wood.
a) Sketch a graph of the function, in the context of this situation.
b) State the domain and range.
c) Explain the significance of the horizontal asymptote.
10. The acceleration due to gravity is inversely proportional to the square of the distance from the centre of Earth.The acceleration due to gravity for a satellite orbiting 7000 km above the centre of Earth is 8.2 m/s2.
a) Write a formula for this relationship
b) Sketch a graph of the relation.
At what height will the acceleration due to gravity be 6.0 m/s2?
11.When a saw is used to cut wood,a certain percent is lost as sawdust, depending on the thickness of the saw-blade. The wood lost is
called the kerf.The percent lost,P(t,can
t+ W
where t is the thickness of the blade and W is the thickness of the wood.both in millimetres
Consider a saw cutting a 30-mm-thick piece of wood.
a) Sketch a graph of the function, in the context of this situation.
b) State the domain and range
c) Explain the significance of the horizontal asymptote.