Question

The blue probe from which you read the time, the range (x), and the height (y) is pulled from the box where the measuring tape is located. The cross-hairs of the probe is placed at the point where the time reads 0.60 s. Questions: 1. Using $v_o = 14$ m/s and $t = 0.60$ s, which angle gives the largest $y$? Explain using trigonometric argument. 2. Using $v_o = 14$ m/s and $t = 0.60$ s, which angle gives the largest $x$? Explain using trigonometric argument. 3. Using $v_o = 22$ m/s, $\theta = 45^\circ$, and $t = 1.59$ s, calculate the maximum vertical position (maximum height), $y_{max} = \frac{1}{2}gt^2$. Does this match the $y_i$ in the table? What is the vertical speed at the maximum height?

          The blue probe from which you read the time, the range (x), and the height (y) is pulled from the
box where the measuring tape is located. The cross-hairs of the probe is placed at the point where
the time reads 0.60 s.

Questions:

1. Using $v_o = 14$ m/s and $t = 0.60$ s, which angle gives the largest $y$?
Explain using trigonometric argument.

2. Using $v_o = 14$ m/s and $t = 0.60$ s, which angle gives the largest $x$?
Explain using trigonometric argument.

3. Using $v_o = 22$ m/s, $\theta = 45^\circ$, and $t = 1.59$ s, calculate the maximum vertical position (maximum
height), $y_{max} = \frac{1}{2}gt^2$. Does this match the $y_i$ in the table? What is the vertical speed at the
maximum height?

The blue probe from which you read the time, the range (x), and the height (y) is pulled from the
box where the measuring tape is located. The cross-hairs of the probe is placed at the point where
the time reads 0.60 s.

Questions:

1. Using vo = 14 m/s and t = 0.60 s, which angle gives the largest y?
Explain using trigonometric argument.

2. Using vo = 14 m/s and t = 0.60 s, which angle gives the largest x?
Explain using trigonometric argument.

3. Using vo = 22 m/s, θ = 45^∘, and t = 1.59 s, calculate the maximum vertical position (maximum
height), ymax = (1)/(2)gt^2. Does this match the yi in the table? What is the vertical speed at the
maximum height?

Added by Tom S.

Question

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