Question

The cdf of the random variable x is given by F_(x)(x)={((1)/(3) ((2)/(3))(x 1)^(2),-1<=x<=0),(0,x<-1):} Find the probability of the events (1)/(3)||<1.

Name: the cdf of the random variable x is given by fxx13 23x 12 1x00x 1 find the probability of the events 131 79887
Uploaded: 2024-02-20T12:49:53-08:00
Duration: 1 min 39 s
Channel: William Fairburn
Description: the cdf of the random variable x is given by fxx13 23x 12 1x00x 1 find the probability of the events 131 79887

          The cdf of the random variable x is given by
F_(x)(x)={((1)/(3) ((2)/(3))(x 1)^(2),-1<=x<=0),(0,x<-1):}
Find the probability of the events  (1)/(3)||<1.

Added by Frank M.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert William Fairburn

02/20/2024

Step 1

The cdf of the random variable X is given by $$F_X(x) = \begin{cases} 1/3 + (2/3)(x + 1)^2 & -1 \le x \le 0 \\ 0 & x < -1. \end{cases}$$ Find the probability of the events $$A = \{X > 1/3\}$$, $$B = \{|X| \ge 1\}$$, $$C = \{|X - 1/3| < 1\}$$, $$D = \{X < 0\}$$. Show more…

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The cdf of the random variable x is given by F_(x)(x)={((1)/(3) ((2)/(3))(x 1)^(2),-1<=x<=0),(0,x<-1):} Find the probability of the events (1)/(3)||<1.