Question

The core refractive index and the cladding index of a planar dielectric waveguide are $n_1$ = 1.600 and $n_2$ = 1.420, respectively. (i) If we would like to design the waveguide with the largest thickness $d$ for which there is only one TE mode at $\lambda_0$ = 1.50 µm, what is $d$? (ii) Calculate the numerical aperture NA and the maximum angle of acceptance $\alpha_0$ (in air) for this waveguide. (iii) Using the waveguide designed in (i), what is the number of possible TE modes if this waveguide is operated at $\lambda_0$ = 0.90 µm instead?

          The core refractive index and the cladding index of a planar dielectric waveguide are
$n_1$ = 1.600 and $n_2$ = 1.420, respectively.
(i)
If we would like to design the waveguide with the largest thickness $d$ for which
there is only one TE mode at $\lambda_0$ = 1.50 µm, what is $d$?
(ii)
Calculate the numerical aperture NA and the maximum angle of acceptance $\alpha_0$
(in air) for this waveguide.
(iii) Using the waveguide designed in (i), what is the number of possible TE modes
if this waveguide is operated at $\lambda_0$ = 0.90 µm instead?

$The core refractive index and the cladding index of a planar dielectric waveguide are n1 = 1.600 and n2 = 1.420, respectively. (i) If we would like to design the waveguide with the largest thickness d for which there is only one TE mode at λ0 = 1.50 µm, what is d? (ii) Calculate the numerical aperture NA and the maximum angle of acceptance α0 (in air) for this waveguide. (iii) Using the waveguide designed in (i), what is the number of possible TE modes if this waveguide is operated at λ0 = 0.90 µm instead?$

Added by Seth B.

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