Question

The desired probability that more than 3 students withdraw was determined to be f(4) + f(5) + + f(18). Recall that the sum of the probabilities for an experiment must be 1. Thus, it must be the case that the sum of the probabilities for each event of x students withdrawing from the class will be 1. That is, f(0) + f(1) + + f(18) = 1. Therefore, we have the following. f(0) + f(1) + f(2) + f(3) + f(4) + + f(18) = 1 Solve this equation for the desired probability, f(4) + f(5) + + f(18). f(4) + f(5) + ... + f(18) = 1 + (f(0) + f(1) + f(2) + f(3))f(4) + f(5) + ... + f(18) = 1 − (f(0) + f(1) + f(2)) f(4) + f(5) + ... + f(18) = 1 + (f(0) + f(1) + f(2))f(4) + f(5) + ... + f(18) = 1 − (f(0) + f(1) + f(2) + f(3))

Name: the desired probability that more than 3 students withdraw was determined to be f4 f5 f18 recall that the sum of the probabilities for an experiment must be 1 thus it must be the case that t 91055
Uploaded: 2024-04-26T12:04:47-08:00
Duration: 1 min 10 s
Channel: Adi S
Description: the desired probability that more than 3 students withdraw was determined to be f4 f5 f18 recall that the sum of the probabilities for an experiment must be 1 thus it must be the case that t 91055

          The desired probability that more than 3 students withdraw was determined to be
f(4) + f(5) +    + f(18).
Recall that the sum of the probabilities for an experiment must be 1. Thus, it must be the case that the sum of the probabilities for each event of x students withdrawing from the class will be 1. That is,
f(0) + f(1) +    + f(18) = 1.
Therefore, we have the following.
f(0) + f(1) + f(2) + f(3) + f(4) +    + f(18) = 1
Solve this equation for the desired probability,
f(4) + f(5) +    + f(18).
f(4) + f(5) + ... + f(18) = 1 + (f(0) + f(1) + f(2) + f(3))f(4) + f(5) + ... + f(18) = 1 − (f(0) + f(1) + f(2))    f(4) + f(5) + ... + f(18) = 1 + (f(0) + f(1) + f(2))f(4) + f(5) + ... + f(18) = 1 − (f(0) + f(1) + f(2) + f(3))

Added by Abigail R.

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