00:01
Hello students, in this question, these are the given loops.
00:04
Here we can see the loop a, the current is flowing in anticlockwise direction, current i current and loop a also encloses loop b in which the current is flowing in clockwise direction and there is loop c and d having current 2i and i and current is flowing in clockwise direction.
00:22
So here we have to see the ampere circuit alone which states that integral b dot dl is equal to mu 0 i enclosed for a current carrying circular coil the line integral of magnetic field will be equal to mu 0 into current enclosed by that loop.
00:50
So from this we will get b equal to mu 0 i by 2 pi r.
00:57
We can give this equation number one.
00:59
So we have to find out which coil have more negative b value.
01:04
So if you look at loop a, the total magnetic field enclosed by loop a will be equal to ba plus bv.
01:15
So in loop a also encloses loop b.
01:18
So in loop a current flowing is i and this flowing in anticlockwise direction.
01:22
So magnetic field ba will be positive.
01:25
So this will be mu 0 i by 2 pi r and the coil b also carrying current i in clockwise direction.
01:34
So magnetic field will be into the plane...