Question

The following numbers of people attended the last 10 screenings of a movie. 196, 197, 197, 198, 199, 207, 208, 210, 211, 292 Complete the parts below to identify any outliers. (a) Let $Q_1$ be the lower quartile and $Q_3$ be the upper quartile of the data set. Find $Q_1$ and $Q_3$ for the data set. $Q_1 = 197$ $Q_3 = 210.5$ (b) Find the interquartile range (IQR) of the data set. IQR = 13.5 (c) Calculate a lower boundary using $Q_1 - 1.5 \cdot IQR$. Calculate an upper boundary using $Q_3 + 1.5 \cdot IQR$. (Note that $1.5 \cdot IQR$ means 1.5 times the IQR.) Lower boundary: 197 Upper boundary: 22 (d) Any values less than the lower boundary or greater than the upper boundary are considered outliers. Identify all the outliers of the data set. If there is more than one outlier, separate them with commas. If there are no outliers, click \"None\" . Outliers: 292 

          The following numbers of people attended the last 10 screenings of a movie.
196, 197, 197, 198, 199, 207, 208, 210, 211, 292
Complete the parts below to identify any outliers.
(a) Let $Q_1$ be the lower quartile and $Q_3$ be the upper quartile of the data set. Find $Q_1$ and $Q_3$ for the data set.
$Q_1 = 197$
$Q_3 = 210.5$
(b) Find the interquartile range (IQR) of the data set.
IQR = 13.5
(c) Calculate a lower boundary using $Q_1 - 1.5 \cdot IQR$. Calculate an upper boundary using $Q_3 + 1.5 \cdot IQR$. (Note that $1.5 \cdot IQR$ means 1.5 times the IQR.)
Lower boundary: 197
Upper boundary: 22
(d) Any values less than the lower boundary or greater than the upper boundary are considered outliers. Identify all the outliers of the data set. If there
is more than one outlier, separate them with commas. If there are no outliers, click \"None\" .
Outliers: 292
Show more…
The following numbers of people attended the last 10 screenings of a movie. 196, 197, 197, 198, 199, 207, 208, 210, 211, 292 Complete the parts below to identify any outliers. (a) Let Q1 be the lower quartile and Q3 be the upper quartile of the data set. Find Q1 and Q3 for the data set. Q1 = 197 Q3 = 210.5 (b) Find the interquartile range (IQR) of the data set. IQR = 13.5 (c) Calculate a lower boundary using Q1 - 1.5 · IQR. Calculate an upper boundary using Q3 + 1.5 · IQR. (Note that 1.5 · IQR means 1.5 times the IQR.) Lower boundary: 197 Upper boundary: 22 (d) Any values less than the lower boundary or greater than the upper boundary are considered outliers. Identify all the outliers of the data set. If there is more than one outlier, separate them with commas. If there are no outliers, click N̈one.̈ Outliers: 292

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Elementary Statistics a Step by Step Approach
Elementary Statistics a Step by Step Approach
Allan G. Bluman 9th Edition
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The following numbers of people attended the last 10 screenings of a movie. 196,197,197,198,199,207,208,210,211,292 Complete the parts below to identify any outliers. (a) Let Q_(1) be the lower quartile and Q_(3) be the upper quartile of the data set. Find Q_(1) and Q_(3) for the data set. (b) Find the interquartile range (IQR) of the data set. (c) Calculate a lower boundary using Q_(1)-1.5*IQR. Calculate an upper boundary using Q_(3)+1.5*IQR. (Note that 1.5*IQR means 1.5 times the IQR.) (d) Any values less than the lower boundary or greater than the upper boundary are considered outliers. Identify all the outliers of the data set. If there is more than one outlier, separate them with commas. If there are no outliers, click "None". The following numbers of people attended the last 10 screenings of a movie. 196,197,197,198,199,207,208,210,211,292 Complete the parts below to identify any outliers. aLet be the lower quartile and be the upper quartile of the data set.Find and for the data set. =197 3=210.5 X 5 bFind the interquartile range(IQR of the data set. IQR=13.5 X cCalculate a lower boundary using -1.5-IQR.Calculate an upper boundary using +1.5-IQR.(Note that 1.5-IQR means 1.5 times the IQR. Lower boundary:197 Upper boundary:22 X 5 is more than one outlier,separate them with commas.If there are no outliers,click"None" Outliers:292 0,0.... None X 5
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Transcript

-
00:01 I am david and i'm here to have your answer your question.
00:03 In the question here we will divide an applier.
00:11 If we will have the first one x will be smaller than the q1, we will minus 1 .5 times in the interquant range.
00:24 And then if you have the x greater than the q3 plus the 1 .5 times in the interquant range.
00:32 Here we are given the data summary for the table.
00:36 Let me bring up the data here.
00:39 And from here, we are given the minimum maximum q1, q3 in the median.
00:44 So first of all, i need to find the interquanta range.
00:47 It will equal to the q3, we minus the q1...
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