Question

The graph shows the x-component of the electric field as a function of position on the x-axis. The electric potential at the origin ($$x=0$$) is 20 V. $$E_x$$ (V/m) 10 0 1 2 3 4 5 6 7 -10 $$x$$ (m) a) What is the electric potential (sign and magnitude) at $$x=6$$ m? Type your answer in Volts. Example: for V($$x=6$$m) = 5 V, type 5. For V($$x=6$$m) = -5 V, type -5. V($$x=6$$ m) = -15 V. b) The potential at point $$x=2$$ m is higher / lower higher than at point $$x=4$$ m?

Name: the graph shows the x component of the electric field as a function of position on the x axis the electric potential at the origin x0 is 20 v ex vm 10 0 1 2 3 4 5 6 7 10 x m a what is the e 17202
Uploaded: 2021-07-11T05:00:34-08:00
Duration: 5 min 25 s
Channel: Supratim Pal
Description: the graph shows the x component of the electric field as a function of position on the x axis the electric potential at the origin x0 is 20 v ex vm 10 0 1 2 3 4 5 6 7 10 x m a what is the e 17202

          The graph shows the x-component of the electric field as a function of position on the x-axis.
The electric potential at the origin ($$x=0$$) is 20 V.
$$E_x$$ (V/m)
10
0
1 2 3 4 5 6 7
-10
$$x$$ (m)
a) What is the electric potential (sign and magnitude) at $$x=6$$ m? Type your answer in Volts.
Example: for V($$x=6$$m) = 5 V, type 5. For V($$x=6$$m) = -5 V, type -5.
V($$x=6$$ m) = -15 V.
b) The potential at point $$x=2$$ m is higher / lower higher than at point $$x=4$$ m?

the graph shows the x component of the electric field as a function of position on the x axis the electric potential at the origin x0 is 20 v ex vm 10 0 1 2 3 4 5 6 7 10 x m a what is the e 17202

Added by Erin W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Supratim Pal

07/11/2021

Step 1

$x$ graph from $x_1$ to $x_2$. We are given that the electric potential at the origin ($x=0$) is $V(0) = 20$ V. Part a) We need to find the electric potential at $x=6$ m, i.e., $V(6)$. We can write: $V(6) - V(0) = -\int_{0}^{6} E_x \, dx$ So, $V(6) = V(0) - Show more…

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The graph shows the x-component of the electric field as a function of position on the x-axis. The electric potential at the origin ($$x=0$$) is 20 V. $$E_x$$ (V/m) 10 0 1 2 3 4 5 6 7 -10 $$x$$ (m) a) What is the electric potential (sign and magnitude) at $$x=6$$ m? Type your answer in Volts. Example: for V($$x=6$$m) = 5 V, type 5. For V($$x=6$$m) = -5 V, type -5. V($$x=6$$ m) = -15 V. b) The potential at point $$x=2$$ m is higher / lower higher than at point $$x=4$$ m?