The inequality $|x-2| \leq 8$ is equivalent to $x \geq 10$ $-6 \leq x \leq 10$ $-10 \leq x \leq 6$ $-10 \leq x \leq 10$ $x \leq -6$
Added by Luis Miguel P.
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Step 2: For an inequality of the form $|u| \leq a$, where $a > 0$, it can be rewritten as $-a \leq u \leq a$. In this case, $u = x-2$ and $a = 8$. Step 3: Apply the rule from Step 2 to the given inequality: $-8 \leq x-2 \leq 8$ Show more…
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