The length of the original piece of cardboard is 18 inches more than the width. If the volume of the box is 360 cubic inches, determine the dimensions of the original piece of cardboard.
Added by Elizabeth A.
Close
Step 1
According to the problem, the length of the original piece of cardboard is 18 inches more than the width, so the length would be x + 18 inches. The volume of a rectangular box is given by the formula V = length * width * height. In this case, the height is not Show more…
Show all steps
Your feedback will help us improve your experience
Joy Squicciarini and 74 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A rectangular piece of cardboard is 2 in. longer than it is wide. A square piece 3 in. on a side is cut from each corner. The sides are then turned up to form an uncovered box of volume 765 in. $^{3}$. Find the dimensions of the original piece of cardboard.
Quadratic Equations, Inequalities, and Functions
Formulas and Further Applications
Solve each problem. A rectangular piece of cardboard is 2 in. longer than it is wide. A square piece 3 in. on a side is cut from each corner. The sides are then turned up to form an uncovered box of volume 765 in. ${ }^{3} .$ Find the dimensions of the original piece of cardboard.
Find the dimensions of the box described. The length is three times the height and the height is one inch less than the width. The volume is 108 cubic inches.
Polynomial and Rational Functions
Zeros of Polynomial Functions
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD