The magnitude M on the Richter scale of an earthquake as a function of its intensity I is given by $$M = \log_{10}\left(\frac{I}{I_0}\right),$$ where $$I_0$$ is some fixed reference level of intensity. The 1906 San Francisco earthquake had a magnitude of 8.3 on the Richter scale. Suppose that at the same time in South America there was an earthquake with magnitude 4.7 that caused only minor damage. How many times more intense was the San Francisco earthquake than the South American one? Answer: Hint: You don't need to know what $$I_0$$ is. Plug in the respective magnitudes and use the log properties you know to compare the resulting values for I in terms of this $$I_0$$.
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Let $M_2$ be the magnitude of the South American earthquake and $I_2$ be its intensity. We are given the formula: $M = \log_{10}\left(\frac{I}{I_0}\right)$ For the San Francisco earthquake: $M_1 = 8.3$ So, $8.3 = \log_{10}\left(\frac{I_1}{I_0}\right)$ For the Show more…
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The 1906 San Francisco earthquake had a magnitude of 8.3 on the Richter scale. At the same time in South America, there was an earthquake with magnitude 4.1 that caused only minor damage. How many times more intense was the San Francisco earthquake than the South American one? Be sure to provide examples in your answer.
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