518, we can use the Poisson distribution. The Poisson probability mass function is given by:
\[
P(X = k) = \frac{e^{-\lambda} \lambda^k}{k!}
\]
where:
- \( \lambda \) is the mean number of occurrences (in this case, 61.518),
- \( k \) is the number of occurrences
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