The mean score of Dellas college's test is 500; the standard deviation is 75. The scores are normally distributed. What percent of the students scored below 400? Know that: according to standard normal distribution table, Z of 1.33 is 0.4082.
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Step 1
We need to find the Z-score for a score of 400, using the formula: Z = (X - μ) / Ļ where X is the score we want to find the Z-score for, μ is the mean score, and Ļ is the standard deviation. Z = (400 - 500) / 75 Z = -1.33 Show moreā¦
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