00:01
Hey there, welcome to numerate.
00:03
We're going to problem here to find the p value and use the p value to compare it to the 0 .05 synonymous level to see if we can reject or fail to reject the null hypothesis.
00:15
Now, with this, let's write down what we're given.
00:19
So we're given an alternative hypothesis here.
00:25
Of the proportion is actually greater than 0 .554.
00:30
Since we're looking at a greater than sign, this implies this is a right -tailed test.
00:46
And with a right -tailed test here, we are given the z score of 1 .34.
00:55
Now, with these stats, we can actually find a p -value already.
00:59
So let's find a p -value, given the z score.
01:04
And our p -value would turn out to be, we turn out to be 0 .0 .0 .09...