The sun acts as a black body radiator with the following...

Name: the sun acts as a black body radiator with the following intensity versus energy graph w fracwm2 ev 20 200 150 100 50 2 3 you are tasked with calculating the efficiency of a polycrystalline 78147
Uploaded: 2024-07-29T20:38:21-08:00
Duration: 6 min 16 s
Channel: Adi S
Description: the sun acts as a black body radiator with the following intensity versus energy graph w fracwm2 ev 20 200 150 100 50 2 3 you are tasked with calculating the efficiency of a polycrystalline 78147

The Sun acts as a black body radiator with the following intensity versus energy graph: $$W$$ $$\frac{W}{m^2 eV}$$ 20 200 150 100 50 2 3 You are tasked with calculating the efficiency of a polycrystalline solar panel with a Silicon base layer (1eV) and a polyphenylene vinylene (PPV) layer that exhibits 2 absorption bands at 3eV and 5eV. Calculate the overall efficiency of the device if the protective coating reflects 26% of the light incident on the panel.

Transcript

00:03 So here it is given, here it is given that it is given that for the observer, the for the observer the absorptance, the absorptance is equal to of 95 % the reflectance, the reflectance is equal to of 5%.

00:33 For the double glazing, for the double glazing, so here, the solar transmission the solar for the double glazing the solar transmissions the solar transmissions that is the tau here is equal to tau for the 0 degree is equal to of 0 .8 0 .8 o and for the tau is equal to of 60 degree this is equal to 0 .7 so now for the solar depth for the solar reflect tense so the explicit into by the row so here this is for row 0 degree this is equal to 0 .15 and for the row for the row 60 degree this value is equal to 0 .29 so here can write for the 0 degree incidence angle incidence angle the total the total reflectance of the collector of the collector of the collector at 0 degree incidence angle so here this will be the reflectance will be the reflectance will be the reflectance will be equal to the reflectance from the observer the reflectance from the observer from the observer plus the transmission the transmitted radiation plus the transmitted radiation radiation so this will be into the reflectance of from the glacing the reflectance from the glazing so now on putting a reference respective values here will get the reflectance from the observer so here the reflections from the observer this will be 0 .05 plus so this will be 0 .84 that is the transmitted radiation into the reflectance from the glazing this will be 0 .15 so here you can write so here you can write the transmitted radiation the transmitted creation is equal to the solar transmitted transmittance so which will be equal to the reflectance will be the reflectance will be the reflections will be have 0 .176 or you can write 17 .6 percent so so at 60 degree incident angle, incidence angle, we can write the total reflectance from the total, the total reflectance, total reflectance of the collector of the collector at 60 degree incidence angle, incidence angle...

Question

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