The wall of a bioreactor is constructed of fiberglass...

Name: the wall of a bioreactor is constructed of fiberglass insulation k 0035 wmk sandwiched between two layers of 1 mm thick sheet metal k 151 wmk the refrigerated space is maintained at 3c and t 23005
Uploaded: 2023-05-24T15:39:22-08:00
Duration: 4 min 21 s
Channel: Supreeta N
Description: the wall of a bioreactor is constructed of fiberglass insulation k 0035 wmk sandwiched between two layers of 1 mm thick sheet metal k 151 wmk the refrigerated space is maintained at 3c and t 23005

The wall of a bioreactor is constructed of fiberglass insulation (k = 0.035 W/m·K) sandwiched between two layers of 1-mm-thick sheet metal (k = 15.1 W/m·K). The refrigerated space is maintained at 3°C, and the average heat transfer coefficients at the inner and outer surfaces of the wall are 4 W/m²·K and 9 W/m²·K, respectively. The process plant temperature averages 25°C. It is observed that condensation occurs on the outer surfaces of the bioreactor when the temperature of the outer surface drops to 20°C. Determine the minimum thickness of fiberglass insulation that needs to be used in the wall in order to avoid condensation on the outer surfaces.

Transcript

00:01 Hi, this is a question based on it where we have the equation for q conduction is given by this k into a t2 minus t1 divided by l and we are given with a value of conductive resistance is given by l by k into a.

00:17 So, now we are given with a kitchen temperature.

00:20 So, kitchen temperature is so, kitchen temperature is 25 degree celsius and we have the outer surface temperature is 20 degree celsius.

00:32 So, now we have q will be equal to so, q is equal to it is h into a into t2 minus so, ta minus t naught.

00:43 So, h is 9.

00:45 So, h output or h in the outer surface is 9 into we have considered so, area is 1 meter square into this is 25 minus 20.

00:58 So, we have this is so, q is 45 joules then we have the convective reactance or convective resistance is given by 1 by h into a and we have the heat transfer is given by t2 minus t1 is equal to q into r.

01:18 So, now we have so, r equivalence is equal to 1 by hi plus l divided by k of fiberglass plus 1 by h naught plus 2 l by k of metal.

01:32 So, we have this is 1 by 4 plus l is so, we have this is l.

01:39 So, l divided by hi is 0 .035 plus 1 by 9 plus this is 2 into 1 into 10 power minus 3 divided by 15 .1 where km is the thermal conductivity of metal.

01:56 So, we have from this equation we have q is equal to t naught minus t outer surface minus inner surface divided by r equivalence.

02:06 So, we can write it as so, we can write q as so, it is t out minus t i divided by r equivalence...

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