00:01
At the fair, there's a barn with chickens and goats.
00:04
The person in charge of that barn counted 53 animals with a total of 142 legs.
00:10
How many of each type of animals in the barn? so the first thing we need to do is we need to set our variables.
00:17
So i'm going to choose c is going to equal the number of chickens, and g is going to equal the number of goats.
00:30
So i'm going to set up two equations.
00:32
The first one is going to have my total of how many animals i have.
00:39
The second one will have a total of the legs.
00:45
Now, my first equation, i have 53 total animals.
00:49
So that means i have my number of chickens plus my number of goats is going to be 53.
00:56
In the next equation, i'm going to use those same variables, but now, since we're talking about a total of legs, i'm going to put 2c, so two legs for every chicken, plus 4g, so four legs for every goat.
01:11
So from here i'm going to solve my system of equations.
01:14
I'm going to choose to use elimination.
01:17
I'm going to multiply this first equation by negative 2, and that will be able to help me cancel out that 2c.
01:24
So distributing the negative 2 through, i get negative 2c minus 2g equals negative 1 .0 .1 .5...