Question

pulls the 100-1b block B via the pulley arrangement in the figure below. The pulleys have no mass and the cord is inextensible. The block is moving up with an acceleration of 10 ft/s². Use this information to answer both Questions 4 and 5. 4. What is the tension in the cord at point A? (A)275 lb (B) 17.2 lb (C) 25.0 lb (D)33.3 lb (E) 32.8 lb $4T=W$ $T=\frac{W}{4}$ 5. What is the acceleration of point A relative to block B?

          pulls the 100-1b block B via the pulley arrangement in the figure below. The pulleys have
no mass and the cord is inextensible. The block is moving up with an acceleration of 10 ft/s². Use
this information to answer both Questions 4 and 5.
4. What is the tension in the cord at point A?
(A)275 lb
(B) 17.2 lb
(C) 25.0 lb
(D)33.3 lb
(E) 32.8 lb
$4T=W$
$T=\frac{W}{4}$
5. What is the acceleration of point A relative to block B?

pulls the 100-1b block B via the pulley arrangement in the figure below. The pulleys have
no mass and the cord is inextensible. The block is moving up with an acceleration of 10 ft/s². Use
this information to answer both Questions 4 and 5.
4. What is the tension in the cord at point A?
(A)275 lb
(B) 17.2 lb
(C) 25.0 lb
(D)33.3 lb
(E) 32.8 lb
4T=W
T=(W)/(4)
5. What is the acceleration of point A relative to block B?

Added by Brian M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Kritika Mishra

04/29/2022

Step 1

We can use the equation T = W + ma, where T is the tension, W is the weight, m is the mass, and a is the acceleration. Show more…

Show all steps

Thanks for your feedback!

this information to answer both Questions 4 and 5. at 4.What is the tension in the cord at point A? A2751b B17.21b C25.01b D33.31b E32.81b x+58 T=W N=n a= 10ft/s2 5. What is the acceleration of point A relative to block B? as V