Question

6. Chords \overline{KM} and \overline{RS} of a circle meet at point L, and KL = RL. Prove that \overline{KR} \parallel \overline{SM}. 1) Construct chords \overline{SM} and \overline{KR}, we now have \triangle SLM + \triangle KLR. (construction) 2) m\angle SLM \cong m\angle KLR (verticle angles) 3)

          6. Chords \overline{KM} and \overline{RS} of a circle meet at point L, and KL = RL. Prove that \overline{KR} \parallel \overline{SM}.
1) Construct chords \overline{SM} and \overline{KR},
we now have \triangle SLM + \triangle KLR.
(construction)
2) m\angle SLM \cong m\angle KLR (verticle angles)
3)

6. Chords KM and RS of a circle meet at point L, and KL = RL. Prove that KR ∥SM.
1) Construct chords SM and KR,
we now have SLM + KLR.
(construction)
2) m∠SLM ≅m∠KLR (verticle angles)
3)

Added by Jill W.

Geometry A Common Core Curriculum

Ron Larson, Laurie Boswell 1st Edition

Instant Answer

Solved by Expert Scott Mcclendon

Step 1

Given that chords KM and RS of a circle meet at point L, and KL = RL. Show more…

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This is all I have so far... Chords KM and RS of a circle meet at point L, and KL = RL. Prove that KR is parallel to SM. Construct chords SM and ER. Now we have âˆ SLM + âˆ AKLR. (conclusion) âˆ LSL = âˆ MKE (vertical angles).