00:01
We're told in this problem that you have two masses stacked on top of each other, m1 and m2.
00:13
In the problem, it references a figure, but because you didn't upload that figure, i'm going to assume it looks like this.
00:21
It could have instead looked like this, where m2 is on the bottom and m1 is on the top.
00:28
And if that were the case, the answer would be different, but the process of solving would be the same, and i'll try and point out the difference when we get to it.
00:41
We're told that mass m1 is equal to 1 .97 kilograms, and that mass m2 is equal to 3 .55 kilograms.
00:54
And we're also told that there is friction between the two blocks where the coefficient of static friction between them is 0 .302.
01:07
But we can ignore friction between the bottom block and the horizontal surface.
01:15
And the question is, if you apply a force f to the top block, what's the largest force you can apply? so that the two blocks do not slide.
01:31
This maximum force is going to occur when we are at the maximum static friction force.
01:41
So if we were to, say, make a free body diagram of the top block, we have our applied force f directed to the right in this picture that i've drawn, and the force of static friction directed to the top block.
01:59
Left.
02:02
As long as these are in balance, the two blocks are not going to slide relative to each other...