Two coils have mutual inductance M = 2.25 * 10^-4 H. The current in the first coil increases at a uniform rate of 530 A/s. What is the magnitude of the induced emf in the second coil?
Added by Rebecca L.
Step 1
Given that the mutual inductance M = 2.25 * 10^-4 H and the current in the first coil increases at a rate of 530 A/s, we can use the formula for mutual inductance: M = (Φ2) / I1 Rearranging the formula to solve for Φ2: Φ2 = M * I1 Substitute the values: Φ2 = Show more…
Show all steps
Your feedback will help us improve your experience
Adi S and 59 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
1) Two coils have mutual inductance M=2.85 x 10-4 H. The current in the first coil increases at a uniform rate of 563 A/s. What is the magnitude of the induced emf in the second coil in Volts?
Adi S.
Two coils have mutual inductance $M=3.25 \times 10^{-4} \mathrm{H}$ . The current $i_{1}$ in the first coil increases at a uniform rate of 830 $\mathrm{A} / \mathrm{s}$ . (a) What is the magnitude of the induced emf in the second coil? Is it constant? (b) Suppose that the current described is in the second coil rather than the first. What is the magnitude of the induced emf in the first coil?
Penny R.
Two coils have mutual inductance $M = 3.25 \times 10^{-4}$ H. The current $i_1$ in the first coil increases at a uniform rate of 830 A/s. (a) What is the magnitude of the induced emf in the second coil? Is it constant? (b) Suppose that the current described is in the second coil rather than the first. What is the magnitude of the induced emf in the first coil?
Inductance
Mutual Inductance
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD