Question

Two different tanks containing water and oil were connected by a triangular gate that can rotate around point A. The depth of the gate is 6 m and the base of the triangle is 4 meters. The tank filled with oil is 6.23 m long and the tank filled with water is 6 m long. If it is known that the gate is at balance (it is not rotating) around A, calculate the specific weight of the oil. (Density of water is 1000 kg/m3) (Hint: follow the steps below: -What is the resultant force of water acted on the gate and where is the center of pressure of this force? - What is the resultant force of oil acted on the gate and where is the center of pressure of this force?) 

          Two different tanks containing water and oil were connected by a triangular gate that can rotate around point A. The depth of the gate is 6 m and the base of the triangle is 4 meters. The tank filled with oil is 6.23 m long and the tank filled with water is 6 m long.
If it is known that the gate is at balance (it is not rotating) around A, calculate the specific weight of the oil. (Density of water is 1000 kg/m3)
(Hint: follow the steps below:
-What is the resultant force of water acted on the gate and where is the center of pressure of this force?
- What is the resultant force of oil acted on the gate and where is the center of pressure of this force?)
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Two different tanks containing water and oil were connected by a triangular gate that can rotate around point A. The depth of the gate is 6 m and the base of the triangle is 4 meters. The tank filled with oil is 6.23 m long and the tank filled with water is 6 m long. If it is known that the gate is at balance (it is not rotating) around A, calculate the specific weight of the oil. (Density of water is 1000 kg/m3) (Hint: follow the steps below: -What is the resultant force of water acted on the gate and where is the center of pressure of this force? - What is the resultant force of oil acted on the gate and where is the center of pressure of this force?)

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Two different tanks containing water and oil were connected by a triangular gate that can rotate around point A. The depth of the gate is 6 m and the base of the triangle is 4 meters. The tank filled with oil is 6.23 m long and the tank filled with water is 6 m long. If it is known that the gate is in balance (it is not rotating) around A, calculate the specific weight of the oil. The density of water is 1000 kg/m^3. (Hint: follow the steps below: - What is the resultant force of water acting on the gate and where is the center of pressure of this force? What is the resultant force of oil acting on the gate and where is the center of pressure of this force?)
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Transcript

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00:01 What will be the results in force at the bottom of the tank? now let's write down our dimensions of our tank.
00:07 Our length is 2 meters, our width is 1 .75 meters, our height of our water is 2 .5 meters, and the height of our oil is 1 .5 meters.
00:21 Now we know that force is equal to mass times acceleration, and we also have that force is equal to mass times gravity when the liquids are static in our tank.
00:31 But we also know mass is equal to density times our volume.
00:37 So we can write our equation of force as follows.
00:40 Our force is equal to rho v g.
00:44 Now we can go ahead and write one for both water and for oil...
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