00:01
In this problem, we are given that there are integers from 1 to 9.
00:06
And amongst these integers, two numbers are selected randomly.
00:12
And we are also given that the sum of these two numbers which are selected, this is even.
00:19
Then we have to find the probability that the numbers which are selected, they are odd numbers.
00:27
So we will consider e here as the event of selecting two numbers which are odd such that the sum is even.
00:36
And we know that we have nine numbers in total.
00:41
And amongst these nine numbers, the number of odd numbers, let's represent that with an o.
00:47
This is equal to five and we have four numbers which are even.
00:52
And as we have to get the sum which is even, then we can see that the even number, if we add them, then in this case, the sum would be even.
01:03
So let's say even is the first even number and e2 is the second even number.
01:07
So if we add them, we will get the sum as even or get there could be possibility that we add two odd numbers because in this case also we will get the sum of even.
01:18
So let's find the total number of outcomes that's possible here...