Two identical urns contain balls. One of the urns has 6 red balls and 3 blue balls. The other urn has 5 red balls and 8 blue balls. An urn is chosen at random and a ball is drawn at random from this urn. If the ball turns out to be red, what is the probability that this is the urn with 6 red balls? Use Bayes' Theorem 13/25 1/2 8 26/41
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Let $U_2$ be the event that the second urn (with 5 red and 8 blue balls) is chosen. Let $R$ be the event that a red ball is drawn. We are given that there are two identical urns, and an urn is chosen at random. So, the prior probabilities of choosing each urn Show more…
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Two identical urns contain balls. One of the urns has 6 red balls and 3 blue balls. The other urn has 5 red balls and 8 blue balls. An urn is chosen at random and a ball is drawn at random from this urn. If the ball turns out to be red, what is the probability that this is the urn with 6 red balls?
Adi S.
Hoan N.
'Two identical urns contain balls. One of the urns has 6 red balls and 3 blue balls. The other urn has 5 red balls and 8 blue balls. An urn is chosen at random and two balls are drawn at random from this urn, without replacement: What is the probability that the second ball is red, given that the first ball is red? "Type your answer as a fraction example: 5/2'
Suman K.
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