Two point charges are fixed on the y axis: a negative point...

Name: Two point charges are fixed on the y axis: a negative point charge q1 = -24 μ C at y1 = +0.16 m and a positive point charge q2 at y2 = +0.37 m. A third point charge q = +9.6 μ C is fixed at the origin. The net electrostatic force exerted on the charge q by the other two charges has a magnitude of 30 N and points in the +y direction. Determine the magnitude of q2.
Uploaded: 2022-01-27T16:37:52-08:00
Duration: 3 min 21 s
Channel: Pritesh Ranjan
Description: Two point charges are fixed on the y axis: a negative point charge q1 = -24 μ C at y1 = +0.16 m and a positive point charge q2 at y2 = +0.37 m. A third point charge q = +9.6 μ C is fixed at the origin. The net electrostatic force exerted on the charge q by the other two charges has a magnitude of 30 N and points in the +y direction. Determine the magnitude of q2.

Two point charges are fixed on the y axis: a negative point charge $q_1 = -24 \mu C$ at $y_1 = +0.16$ m and a positive point charge $q_2$ at $y_2 = +0.37$ m. A third point charge $q = +9.6 \mu C$ is fixed at the origin. The net electrostatic force exerted on the charge q by the other two charges has a magnitude of 30 N and points in the $+y$ direction. Determine the magnitude of $q_2$.

Transcript

00:01 In this problem, we have been given that there are two point charges, q1 and q2.

00:06 So these two point charges are placed on the y axis such that the distance of placement of this q1 from origin, that's 0 .19 meters.

00:17 And this q2 is placed at a distance of 0 .34 meters.

00:22 Also, we have been given the values of this charge.

00:26 So q2 is given as positive, and we have to determine the magnitude of the amount.

00:30 Of this q2 charge, q1 is given as minus 24 microculum, which is minus 24 times 10 raise to minus 6 column.

00:40 Q here, it's another charge that's kept on the origin, which has the value of 8 .8 microculum, and that will be 8 .8 times 10 raise to minus 6 column.

00:52 Provided that now we are given that the total electric force, that this charge present at origin experiences, that is along the positive wide direction and it has magnitude of 31 newtons so we observed that the charge placed at the origin that's positive and the charge present at point one nine meter that's negative and the q2 charge that's positive so this charge placed at the origin that will experience a repulsive force because of q2 charge and the charge at this origin because of q1 it will experience a repulsive force it will be attractive here because it's directed towards the line joining this positive and negative charge.

01:37 So the force between q and q1 that is attractive and the force between q and q2 that is repulsive.

01:48 But anyways we are given that the net force is along the positive y direction and that's having magnitude 31 newtons...

Question

Please give Ace some feedback