00:01
Hi, i'm david and i'm here to help me answer your question.
00:03
Now let me bring up your question here.
00:06
In the question here, we are going to discuss about the competence interval from the standard division.
00:12
Let me remind you that the composite interval for the sigma, the sigma will be between the n minus 1 times the s square over the k square on the n minus 1 degree freedom.
00:26
And then unfound over 2 on the rugby the n minus 1 time with the s square divided by the k square and minus 1 1 equivide with the level 1 minus unfound over 2 and in this question here we're given the c equal to the 098 therefore we can find the k square also the n equal to the 28 with these two information we can find the two values first will be the k square with the n minus one degree uh sorry this one i forgot to put under the square root here now for the first value will be the n minus 1 degree with them and equal to the 28 minus 1 will be the 27 and for our confidence 0 .98 and 5 equals to the 0 0 0 2 defined by 2 equal to the 0 .01.
01:25
And if we compute this one, we have the k square with the 27 degree freedom.
01:31
Here we have this one would be the under level 0 .0 1.
01:39
Again, equal to the 46 .96 to 94.
01:47
And the second critical value here, 1 minus 0 .01 equal to the 0 .04...