Question

Use the information given below to find $\tan(\alpha-\beta)$.\\ $\sin \alpha = \frac{3}{5}$, with $\alpha$ in quadrant I\\ $\tan \beta = \frac{12}{5}$, with $\beta$ in quadrant III\\ Give the exact answer, not a decimal approximation.\\ $\tan(\alpha - \beta) = $

          Use the information given below to find $\tan(\alpha-\beta)$.\\
$\sin \alpha = \frac{3}{5}$, with $\alpha$ in quadrant I\\
$\tan \beta = \frac{12}{5}$, with $\beta$ in quadrant III\\
Give the exact answer, not a decimal approximation.\\
$\tan(\alpha - \beta) = $

Use the information given below to find tan(α-β).

sinα = (3)/(5), with α in quadrant I

tanβ = (12)/(5), with β in quadrant III

Give the exact answer, not a decimal approximation.

tan(α - β) =

Added by Daniel G.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Kathleen Carty

06/23/2022

Step 1

We can use the Pythagorean identity to find cos(a): cos(a) = sqrt(1 - sin^2(a)) cos(a) = sqrt(1 - (3/5)^2) cos(a) = sqrt(1 - 9/25) cos(a) = sqrt(16/25) cos(a) = 4/5 Show more…

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