Question

Use the Law of Sines to solve for all possible triangles that satisfy the given conditions. (If an answer does not exist, enter DNE. Enter all angles in degrees. Round the length to one decimal place.) a = 27, b = 12, \angle A = 112^\circ

          Use the Law of Sines to solve for all possible triangles that satisfy the given conditions. (If an answer does not exist, enter DNE. Enter all angles in degrees. Round the length to one decimal place.)
a = 27, b = 12, \angle A = 112^\circ

Use the Law of Sines to solve for all possible triangles that satisfy the given conditions. (If an answer does not exist, enter DNE. Enter all angles in degrees. Round the length to one decimal place.)
a = 27, b = 12, ∠A = 112^∘

Added by Kevin B.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Hemraj Kumawat

10/21/2022

Step 1

Given: a = 27, b = 12, A = 112 degrees Using the Law of Sines: sin(A)/a = sin(B)/b sin(112)/27 = sin(B)/12 sin(B) = 12*sin(112)/27 sin(B) ≈ 0.464 B ≈ sin^(-1)(0.464) B ≈ 28.1 degrees Show more…

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Use the Law of Sines to solve for all possible triangles that satisfy the given conditions. There may be two triangles, one triangle, or no triangles that satisfy the given conditions. (If an answer does not exist, enter DNE. Enter all angles in degrees. Round the length to one decimal place.) ,a=27,b=12(,)/(_(A))=112deg ()/(_(B)) ,=()/(_(C)) ,= c,= = a=27b=12A=112 exist, enter DNE. Enter all angles in degrees. Round the length to one decimal place.