using your sample mean, n=72900 and sigma =2430 test the claim the mean is different to $90
Added by Laura M.
Step 1
In this case, the claim is that the mean is different from $90. Therefore, the hypotheses are: - H0: μ = $90 (The population mean is equal to $90) - H1: μ ≠ $90 (The population mean is not equal to $90) Show more…
Show all steps
Close
Your feedback will help us improve your experience
Hossam Mohamed and 91 other Intro Stats / AP Statistics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Assume the sample is from a normally distributed population and construct the indicated confidence intervals for $(a)$ the population variance $\sigma^{2}$ and $(b)$ the population standard deviation $\sigma .$ Interpret the results. The prices of a random sample of 20 new motorcycles have a sample standard deviation of $\$ 3900 .$ Use a $90 \%$ level of confidence.
Confidence Intervals
Confidence Intervals for Variance and Standard Deviation
Use technology to help you test the claim about the population mean, at the given level of significance, using the given sample statistics. Assume the population is normally distributed. Claim: μ > 1290; α = 0.07; σ = 197.00. Sample statistics: x̄ = 1318.92, n = 200.
Adi S.
Two samples, sizes 40 and 50 respectively, are taken from a population with unknown mean μ and unknown variance σ2 . The data is shown below. X1 18 19 20 21 22 f1 3 7 15 10 5 X2 18 19 20 21 22 23 f2 10 21 8 6 3 2 Using the data from the two samples above, obtain unbiased estimates of i. The population mean µ ii. The population variance σ2
Jon S.
Recommended Textbooks
Elementary Statistics a Step by Step Approach
The Practice of Statistics for AP
Introductory Statistics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD